Question

find the modulus of the complex number 3+4i/1+7i

Answer 1

$\frac{3 + 4i}{1 + 7i} \\ = \frac{(3 + 4i)(1 - 7i)}{ {1}^{2} + {7}^{2} } \\ = \frac{31 - 17i}{50} \\ = > | \frac{31 - 17i}{50} | \\ = \frac{ {31}^{2} + {17}^{2} }{50} \\ = \frac{1250}{50} \\ = 25$

Answer 2

3#+5
9=80
Ha 888€+
31
6+9
4+5(1)??98=
000 +8
85