Question

find the modulus of z = -1 +√3i​

Answer 1

Step-by-step explanation:

z=−1−i

3

Let rcosθ=−1andrsinθ=−

3

On squaring and adding, we obtain

(rcosθ)

2

+(rsinθ)

2

=(−1)

2

+(−

3

)

2

⇒r

2

(cos

2

θ+sin

2

θ)=1+3

⇒r

2

=4[cos

2

θ+sin

2

θ=1]

⇒r=

4

=2 (Conventionally,r>0 )

∴ Modulus of z i.e ∣z∣=2

Answer 2

Answer:

I hope it helps you

Step-by-step explanation:

hope it helps you