Question

Find the molality and molarity of 15% solution of H^2SO^4 (density = 1.020g/cm^3.

Answer 1

Let the volume of sol. =100
w of h2s04 =15gm
Mw=98
n
$15 \div 98 =$
. 15
molarity is equal to number of moles upon volume of solution in litre
Volume of soln=
$100 \div 1.02 = 98 \\ molrity = .15 \div .098 = 1.56$