Question

find the molality and molarity of a 15percent solution of h2so4 (density=1.02)​

Answer 1

HEYA GE ❤

★ Hope it helps you ..

Answer 2

Molecular weight of

H

2

S

O

4

=2×1+32+64

H

2

S

O

4

=

2

×

1

+

32

+

64

⇒98gmo

l

−1

⇒

98

g

m

o

l

−

1

M=

15g×1000

98g/mol×115g×1.02g/c

m

3

M

=

15

g

×

1000

98

g

/

m

o

l

×

115

g

×

1.02

g

/

c

m

3

=

15000

11495.4

=

15000

11495.4

molar

=1.3048

=

1.3048

molar

m (molality) =

W

B

×1000

W

B

×100g

W

B

×

1000

W

B

×

100

g

⇒

15g×10

98gmo

l

−1

⇒

15

g

×

10

98

g

m

o

l

−

1

⇒

150

98

⇒

150

98

⇒1.53

⇒

1.53

molal