Find the molality of 15℅solution ofH2s04 by mass.
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Molality=Wb*1000/Wb*100g
=15*10/98=150/98=1.53
Make it the brainliest answer
=15*10/98=150/98=1.53
Make it the brainliest answer
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Answered by
1
weight of solute(W2 ) = 15g
weight of solvent(W1) = 100g
molar mass of H2SO4 (M1 )= 98g
molality = W2/ W1 M2
= 15 / ( 100x98 ) x 1000
= 1.53 m
hope this was helpful
weight of solvent(W1) = 100g
molar mass of H2SO4 (M1 )= 98g
molality = W2/ W1 M2
= 15 / ( 100x98 ) x 1000
= 1.53 m
hope this was helpful
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