Question

Find the molality of a solution contains 1.325 g and Na2CO3 dissolved in 250g water

Answer 1

M= no of moles / mass of solvent in kg
M= 1.325*1000/250*106*1000
M=0.05 m

Answer 2

Answer:

molality=mole÷kg of solvent

given   mass=1.325g pf na2co3(molar mass =106)

solvent =250g=0.25kgs

mole=mass÷molar mass

        = 1.325÷106

         =0.8

molality=0.8÷0.25

             =3.2kgs

Explanation: