Chemistry, asked by Abinanadana, 9 months ago

Find the molality of a solution contains 1.325 g and Na2CO3 dissolved in 250g water

Answers

Answered by anjali300403

1

M= no of moles / mass of solvent in kg
M= 1.325*1000/250*106*1000
M=0.05 m

Answered by linypearl4

0

Answer:

molality=mole÷kg of solvent

given mass=1.325g pf na2co3(molar mass =106)

solvent =250g=0.25kgs

mole=mass÷molar mass

= 1.325÷106

=0.8

molality=0.8÷0.25

=3.2kgs

Explanation:

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