find the molality of the solution when 149gm of koh is disolved in 1.5 kg of solvent
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Answer:
Explanation:
The formula for molar concentration
c
is
c
=
moles
litres
Moles
=
5.6
g KOH
×
1 mol KOH
56.11
g KOH
=
0.0998 mol KOH
Litres
=
250
mL
×
1 L
1000
mL
=
0.2500 L
c
=
0.0998 mol
0.2500 L
=
0.40 mol/L
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