Question

find the molality of the solution when 149gm of koh is disolved in 1.5 kg of solvent

Answer 1

Answer:

Explanation:

The formula for molar concentration

c

is

c

=

moles

litres

Moles

=

5.6

g KOH

×

1 mol KOH

56.11

g KOH

=

0.0998 mol KOH

Litres

=

250

mL

×

1 L

1000

mL

=

0.2500 L

c

=

0.0998 mol

0.2500 L

=

0.40 mol/L