Chemistry, asked by kashab7196, 11 months ago

Find the molarity and molality of 15 solution of h2so4

Answers

Answered by tanusahu8268gmail
8

Explanation:

No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 mol

Weight of solvent = 100g - 15g = 85g = 85 × 10^-3 kg

Molality = Moles of solute / Weight of Solvent in kg

= 0.153 / (85 × 10^-3)

= 1.8 m

Molality of given solution is 1.8 m ……[1]

Volume of solution = Mass of solution / Density

= 100 g / 1.1 g/cm^3

= 90.90 cm^3

= 0.090 Litres

Molarity = Moles of solute / Volume of solution in litres

= 0.153 / 0.090

≈ 1.7 M

Molarity of given solution is 1.7 M ……[2]

Answered by yeshapradeep200
4

15% H₂SO₄ solution means 15 g of H₂SO₄ is present in 100 g of Water.

No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 mol

Weight of solvent = 100g - 15g = 85g = 85 × 10^-3 kg

Molality = Moles of solute / Weight of Solvent in kg

= 0.153 / (85 × 10^-3)

= 1.8 m

Molality of given solution is 1.8 m ……[1]

Volume of solution = Mass of solution / Density

= 100 g / 1.1 g/cm^3

= 90.90 cm^3

= 0.090 Litres

Molarity = Moles of solute / Volume of solution in litres

= 0.153 / 0.090

≈ 1.7 M

Molarity of given solution is 1.7 M ……[2]

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