Question

find the molarity and strength of given KMnO4 solution. You are provided with M/20 oxalic acid solution.with full observation table and calculation
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Answer 1

Answer:

The molarity and strength of the given KMnO₄ solution is 0.015 M.

Explanation:

We are given the molarity of oxalic acid to be $\frac{M}{20}$, and its volume to be 100 mL.

We are to find the molarity of KMnO₄ in the solution.

We take 10 mL of oxalic acid in the pipette and pour it into the beaker, followed by titration with the given KMnO₄.

We take 3 readings, so as to avoid errors of various kinds -

1. Initial = 1 mL
  Final = 13 mL
  Volume used (KMnO₄) = 12 mL

2. Initial = 13 mL
   Final = 26.3 mL
   Volume used (KMnO₄) = 13.3 mL

3. Initial = 26.5 mL
   Final = 39.8 mL
   Volume used (KMnO₄) = 13.3 mL

Thus, we have to concordant values to be 13.3 mL, which we will take as our KMnO₄ volume used.

We now have the formula to be -

$\frac{M_1 \times V_1}{M_2 \times V_2} = \frac{2}{5} \\\\\implies M_1 = \frac{2 \times M_2 \times V_2}{5 \times V_1}\\\\ M_1 = \frac{2 \times 10}{5 \times 20 \times 13.3} \\\\M_1 = \frac{2}{10 \times 13.3} \\\\\\M_1 = 0.015$

Thus, we have the molarity of the given KMnO₄ solution to be 0.015 M.

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Answer 2

Answer:

The correct answer of this question is$0.015 M.$

Explanation:

Given - M/20 oxalic acid solution.

To Find - find the molarity and strength of given KMnO4 solution.

Oxalic acid will have a molarity of $M/20$ and a volume of $100$ mL.

We pipette 10 mL of oxalic acid into the beaker and conduct a titration using the supplied KMnO4.

In order to prevent errors of all kinds, we take 3 readings.

1. Initial = $1 mL$

 Final = $13 mL$

 Volume used (KMnO₄) = $12 mL$

2. Initial = $13 mL$

  Final = $26.3 mL$

  Volume used (KMnO₄) =$13.3 mL$

3. Initial = $26.5 mL$

  Final = $39.8 mL$

  Volume used (KMnO₄) = $13.3 mL$

so,  the molarity of the given KMnO₄ solution to be 0.015 M.