find the molarity of 49%w/v h^3po^4
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Answer:
Given, 49% weight by volume HCl solution
Therefore, weight of HCl in 1ml of solution = specific gravity x 49%
= 1.41 x 49/100
=.6909 g/ml
Weight of HCl in 1000 ml of solution = 0.6909 x 1000 = 690.9 g
Molarity = weight of HCl in 1000 ml / mol.weight of HCl
= 690.9/36.4
= 18.9 M
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