Question

find the molarity of a solute in final solution when 200ml ,2M (molarity ) NaOH solution is mixed with 300 ml and 1 M NaOH solution and final solution is made up to 2 litre,?????






Pls solve it quickly nd pls if anyone don't know how to solve than don't answer.....pls help.....guys

Answer 1

As no of moles remain the same,

Msol Vsoln=M1V1+M2V2

V1=300ml=0.3L

V2=200ml=0.2L

M soln Vsoln=1×0.3+2×0.2

M soln=0.7/2=0.35M

I hope this helps ( ╹▽╹ )

Answer 2

Answer:

The answer is 7/20 mole.

Explanation:

you can use rhe formula

M1V1+M2V2=MV

where

M1= molarity of NaOH in first solution

M2= molarity of NaOH in second solution

V1=Volume of first solution in ml

V2=Volume of second solution in ml

M=Molarity of final solution

V=Volume of final solution in ml

Hope it helps you

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