find the molarity of a solution prepared by dissolving 7.1 gram of N a2 S o4 in hundred ml of H2O
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Given:
Sample mass =7.1g
Volume = 100 ml
☆Mwt of Na2SO4= 23×2+32+16×4=142g
☆Number of moles = ms ÷ mwt =7.1÷142= 0.05 mol
☆To calculate molarity equal number of moles ÷ volume in litre
☆M= n÷v= 0.05 ÷ 0.1 = 0.5 mol/l
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