Question

Find the molarity of H2SO4 solution whose specific gravity is 1.98 g/ml and 95%by volume H2SO4. (a)7.412 (b)8.412 (c)9.412 (d)10.412​

Answer 1

$\large{\underline{\texttt{QUESTION:}}}$

Find the molarity of H2SO4 solution whose specific gravity is 1.98 g/ml and 95%by volume H2SO4.

(a)7.412 (b)8.412 (c)9.412 (d)10.412

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$\large{\underline{\texttt{\green{ANSWER:}}}}$

(c) 9.412

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$\large{\underline{\texttt{\green{EXPLANATION:}}}}$

$\mapsto$ H2SO4 is 95% by volume

$\mapsto$ Wt. of H2SO4 = 95g

$\mapsto$ Vol of solution = 100ml

$\therefore$ Moles of H2SO4 =95/98

and weight of solution = 100 x 1.98 g

$\implies$ Weight of water = 198 - 95 = 103 g

$\implies$ Molality = 95 x 1000/98 x 103 = 9.412

Hence molality of H2SO4 solution is 9.412

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