find the molarity of hcl is 1.5×10^-4 then ph of hcl is
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it follows step 2
i.e., concentration of acid = 10^-8 + 10^-7
= 10^-7 × 1.1
Then pH = -log(1.1×10^-7) =7 - log(1.1)
= 7 - 0.02 = 6.98
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Darshan Paithankar
Answered 2 years ago
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