Question

Find the molarity of the following solution 60 gm Ca(OH)2 dissolved in 1800 ml aqueous solution.​

Answer 1

Answer:

SInce dissociation is complete, hence, α=1

Now, we know that,  

pH+pOH=14

pOH=14−pH=14−10.65=3.35

pOH=−log  

10

​  

[OH −OH  −OH ]=Antilog(−3.35)

or 10  −3.35 =4.46×10 ^−4

mol/dm  3Now,

[OH  

−

]=nαC

where, n=Acidity of the given base or no. of replaceable OH  

−

 ion=2

Hence,

C=  

2×1

4.46×10  

−4

 

​  

=2.23×10  

−4

 

We know that

C= Molarity of the solution=  

Volume of solution in dm  

3

 

No. of moles of solute

​  

 

Hence, no. of moles of Ca(OH)  

2

​  

=2.23×10  

−4

×0.25=5.57×10  

−5

mol

Explanation:

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Answer 2

Answer:

this is the right answer