Question

find the mole fraction of benzene in a solution which is 30% by mass in CCL4

Answer 1

Hey !!

Let the mass of solution be 100 g

Mass of Benzene = 30 g

Mass of carbon tetrachloride = 100 g - 30 g = 770 g

Number of moles of benzene = Mass / Molar mass

                     = 30 g / 78 g mol⁻¹

                     = 0.385 mol

Number of moles of carbon tetrachloride = Mass / Molar mass

                   = 70 g / 154 g mol⁻¹

                   = 0.455 mol

Mole fraction of benzene = Mass of benzene / Moles of benzene + Moles of tetrachloride

                 = 0.385 mol / 0.840 mol

FINAL RESULT  :- 0.458

Hope it helps you !!