Question

find the mole fraction of carbon. 2C+(O)2=2CO. C=49 g​

Answer 1

Explanation:

Let us assume that initially, 100 moles of CO

2

are present.

2 moles of CO

2

decompose to form 2 moles of CO and 1 mole of O

2

.

100−2=98 moles of CO

2

remains.

The mole fraction of CO

2

at equilibrium =

100

98

=0.98

The partial pressure of CO

2

at equilibrium =0.98×1atm=0.98atm.

The mole fraction of CO at equilibrium =

100

2

=0.02

The partial pressure of CO at equilibrium =0.02×1atm=0.02atm.

The mole fraction of O

2

at equilibrium =

100

1

=0.01

The partial pressure of O

2

at equilibrium =0.01×1atm=0.01atm.

K

P

=

P

CO

2

2

P

CO

2

P

O

2

K

P

=

(0.98atm)

2

(0.02atm)

2

×0.01atm

K

P

=4.12×10

−6

atm