find the molecular formula of an organic compound containing c, h and oxygen in the mass ratio of 3:1:4
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An organic compound contains C,H and O. If C (%) : H(%) = 6:1, 700 g of the total mass of C and H (in the compound) will contain 600 g C and 100 g H.
The number of moles of C are
12
600
=50
The number of moles of H are
1
100
=100
Thus the ratio of the number of moles C:H is 50:100 or 1:2.
The molecular formula of the compound is C
x
H
2x
O
y
The balanced chemical equation for the combustion reaction is
C
x
H
2x
O
y
+(1.5x−0.5y)O
2
→xCO
2
+xH
2
O
2y=2(1.5x−0.5y)
y=1.5x−0.5y
x=y
Hence, the molecular formula is C
x
H
2x
O
x
or CH
2
O
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