Question

Find the molecular mass of the following i) HNO3 II) CH3COOH III) CaCO3 (1.5) ( Atomic mass of H=1; N=14 ; O=16 ; Ca=40 ; C=12

Answer 1

Explanation:

HNO3

=1+14+16×3

=1+14+48

=15+48

=63u

CH3COOH

=2×12+4×1+2×16

=24+4+32

=28+32

=50u

CaCO3

=40+12+3×16

=40+12+48

=52+48

=100