Find the molecular mass of the following i) HNO3 II) CH3COOH III) CaCO3 (1.5) ( Atomic mass of H=1; N=14 ; O=16 ; Ca=40 ; C=12
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Explanation:
HNO3
=1+14+16×3
=1+14+48
=15+48
=63u
CH3COOH
=2×12+4×1+2×16
=24+4+32
=28+32
=50u
CaCO3
=40+12+3×16
=40+12+48
=52+48
=100
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