Question

Find the molecular weight of Mg3(P04)2 step by step

Answer 1

Answer:

262grams

Explanation:

Mg3(PO4)2

=> 3Mg , 2P , 8O

molecular weight = 3×molecular weight of Mg + 2× molecular weight of P + 8× molecular weight of O

=> molecular weight = 3(24) + 2×31 + 8(16)

=> molecular weight = 72 + 62 + 128

=> molecular weight = 262gram

Answer 2

Question:

Find the molecular weight of Mg₃(PO₄)₂

Subject:

Chemistry

Topic:

Finding the molecular weight of the given compound

Solution:

To find the molecular weight of Mg₃(PO₄)₂

$\boxed{ \begin{minipage}{10 cm} Atomic Weight:\\\\\\Atomic Weight of Magnesium = 24\\\\Atomic Weight of Phosphorus =31\\\\Atomic Weight of Oxygen = 16\\\\\\Number of Atoms Present:\\\\\\Number of Magnesium Atoms =3\\\\Number of Phosphorous Atoms = 2\\\\Number of Oxygen Atoms = 8\\\\\\Molecular Weight of Mg_3(P04)_2=\\\\\\ Mg=3\times24 = 72\\\\ P=2\times31 = 62\\\\ O=8\times16=128\\\\\\ Molecular Weight of Mg_3(P04)_2=72+62+128=262amu\end{minipage} }$

Answer:

Molecular Weight of Mg₃(PO₄)₂ = 262 amu