Question

Find the molecular weight of peroxidase anhydrase enzyme when 0.5% of se is present in it

Answer 1

) 1.568 x 104

Explanation: In peroxidase anhydrous enzyme 0.5% Se is present means, 0.5 g Se is present in 100 g of enzyme. In a molecule of enzyme one Se atom must be present. Hence 78.4 g Se will be present in 100/0.5 x 78.4 = 1.568 x 10^4