Find the moles and mass in 1.12 litre of ozone at STP
Answers
Answered by
24
Answer:
Explanation:
OZONE= O3
MOLECULAR MASS OF OZONE=48 G
WE KNOW THAT, UNDER STANDARD CONDITIONS OF TEMPERATURE AND PRESSURE,
I MOLE= 22.4 LITRE
GIVEN 1.12 LITRES,
MOLES=1.12/22.4
=0.05 MOLES
I MOLE= 48 G
0.05 MOLES=2.4 G
THEREFORE,
NUMBER OF MOLES= 0.05
MASS =2.4 G.
HOPE THIS HELPS.
Answered by
3
Answer:
0.05
Explanation:
since 22.4 L of gas contain 1 mole at stp
then 1.12 L of gas contains =1.12/22.4 moles
= 0.05
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