Question

find the moles in
12.044 × 10 to the power 22 no. of neon atoms

Answer 1

1 mole of neon atoms contain 6.022×10²³ atoms

12.044×10²² atoms = $\frac{12.044 \times 10^{22}}{6.022 \times 10^{23}}\ moles = 0.2\ moles$

Answer 2

6.022 X 10∧23 atoms of neon atom   = 1 mole                
1 atom of neon                                 =1/ 6.022 X 10∧23 
12.044 X 10∧22  atoms of neon    = [(1/6.022 X 10∧23) x 12.044 X 10∧22 ]moles
                                                  =  2 X 10∧-1