Question

Find the moment of force 20N about an axis of rotation at a distance of 0.5 from the force.​

Answer 1

Answer:

10 Nm

Explanation:

Moment Of Force :- The Turning effect of a force acting on a body about the axis passing through a fixed point is called Moment Of Force .

Moment = Force * Perpendicular distance .

= 20 N * 0.5 m

= 10 N.m

Hence Moment of Force is 10N.m

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Answer 2

Question-

Find the moment of force of 20N about axis of rotation at distance 0.5m from the force.

Given-

Force = 20N

⊥ Distance = 0.5m

To find-

Moment of force

Calculation-

We know,

${\underline {\underline {\boxed {\red {\sf {Moment \: of \: force = Force \times ⊥ Distance }}}}}}$

$\sf {☞ \: Moment \:of \:force = F × ⊥ Distance}$

$\sf {☞ \: Moment \: of\: force = 20N × 0.5 m}$

$\sf { ☞ \:Moment \: of \:force = 10 Nm }$

Therefore, the moment of force of 20N about axis of rotation at distance 0.5m from the force is 10Nm.

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