Question

Find the moment of force of 20 N about an axis of rotation at the distance 0.5m from the force.

Answer 1

Moment Of Force :- The Turning effect of a force acting on a body about the axis passing through a fixed point is called Moment Of Force .

The moment of force is equal to product of the magnitude of the force and the perpendicular distance of the line of action of the force from the axis of rotation

Coming Back to the Question .

tau = Force * Perpendicular distance .

= 20 N * 0.5 m

= 10 N.m

Answer 2

Question-

Find the moment of force of 20N about axis of rotation at distance 0.5m from the force.

Given-

• Force = 20N
• ⊥ Distance = 0.5m

To find-

• Moment of force

Calculation-

We know,

${\underline {\underline {\boxed {\red {\sf {Moment \: of \: force = Force \times ⊥ Distance }}}}}}$

$\sf {☞ \: Moment \:of \:force = F × ⊥ Distance}$

$\sf {☞ \: Moment \: of\: force = 20N × 0.5 m}$

$\sf { ☞ \:Moment \: of \:force = 10 Nm }$

Therefore, the moment of force of 20N about axis of rotation at distance 0.5m from the force is 10Nm.

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