Question

Find the moment of force of 20 Newton about an axis of rotation at distance of 0.5 metre from the force

Answer 1

Answer:10 Nm

Explanation:We know that , moment of force or torque is equals to the product of force applied with with the distance from the line of action of the force. Then,

Force=20Newton(N)

Distance=0.5meter(m)

Torque=Force*Distance

=20*0.5

=10Nm(Ans)