Question

Find the moment of force of 20 Newton about an axis of rotation and distance 0.5m from the force

Answer 1

we know that moment of force = F*s

= 20 * 0.5 = 10 N m

Answer 2

Question-

Find the moment of force of 20N about axis of rotation at distance 0.5m from the force.

Given-

• Force = 20N
• ⊥ Distance = 0.5m

To find-

• Moment of force

Calculation-

We know,

${\underline {\underline {\boxed {\red {\sf {Moment \: of \: force = Force \times ⊥ Distance }}}}}}$

$\sf {☞ \: Moment \:of \:force = F × ⊥ Distance}$

$\sf {☞ \: Moment \: of\: force = 20N × 0.5 m}$

$\sf { ☞ \:Moment \: of \:force = 10 Nm }$

Therefore, the moment of force of 20N about axis of rotation at distance 0.5m from the force is 10Nm.

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