Find the moment of force of 20N about an axis of rotation at a distance of 0.5 m from the force
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Answered by
3
Answer:
1nm
Explanation:
Given force -f=5m
d=20cm =0=2cm
moment of force =f*d
5n*0.2m =1nm
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Answered by
0
Answer:
1nm
Explanation:
Given force -f=5m
d=20cm=0=2cm
moment of force=f=d
5n* 0.2m = 1nm
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