Physics, asked by om1979786, 5 hours ago

Find the moment of force of 40 N about an exis of rotation at a distance of 0.5 m from the force

Answers

Answered by kswasti71

0

Answer:

10 nm

Explanation:

Moment of force = Force \times× perpendicular distance of force from point of rotation

= F\times× \bot⊥ distance

= 20N 0.5m

= 10Nm

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