Question

Find the moment of inertia of a plate cut in shape of a right angled triangle of mass m, side ac=bc=a about an axis perpendicular to the plane of the plate and passing through the midpoint of side ab

Answer 1

Hey dear,

● Answer- ma^2/12

● Explaination-
Let's attach similar isosceles right angled triangle with the first with hypotenuse touching.

Moment of inertia at the centre (middle of hypotenuse) is
I = (2m)(a)^2 / 12
I = ma^2/6

Here, M.I. at hypotenuse due to single triangle will be half of that i.e. ma^2/12.

Hope this is helpful...