Find the moment of inertia of a rod of mass 2m length b and having 2 particles each of mass m at both ends
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hey guys
here is your answer of physics
moment of inertia = mL²
here, m=4kg
l=2m
thus moment inertia = 4×2×2
= 16kgm²
here is your answer of physics
moment of inertia = mL²
here, m=4kg
l=2m
thus moment inertia = 4×2×2
= 16kgm²
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