Question

find the moment of inertia of rod of Mass 10kg and length 5m about axis passing through one end of rod. ​

Answer 1

Answer:

Ans-

This is step by step explanation

Mass of rod =M

Length of Rod =L

Distance of rods edge from center =2L/2L

Moment of inertia of rod at center Ic=1/12 ML^2

For moment of inertia at edge apply parallel axis theorem.

M( 2L)2

I= 12

1ML

2+M(2L)2= 31ML 2

moment of inertia at edge is=31

ML2