Question

Find the momentum (in MeV/c) of an electron whose speed is0.600c.​

Answer 1

Answer:

0.3832 MeV/c

Explanation:

$momentum = \gamma mv \\ \gamma = \frac{1}{ \sqrt{1 - \frac{ {v}^{2} }{ {c}^{2} } } } \\ now \\ \: \: momentum = \frac{mv}{ \sqrt{1 - \frac{ {v}^{2} }{ {c}^{2} } } } \\ ginev \: \: v = 0.6c \: \: and \: m = 0.511 \frac{mev}{ {c}^{2} } \\ now \: \: \: momemtum = \frac{0.511 \frac{mev}{ {c}^{2} } \times 0.6c }{ \sqrt{1 - \frac{( {0.6c})^{2} }{ {c}^{2} } } } \\ = \frac{0.3066 \frac{mev}{c} }{ \sqrt{1 - 0.36} } = \frac{0.3066 \frac{mev}{c} }{ \sqrt{0.64} } \\ = \frac{0.3066 \frac{mev}{c} }{ 0.8} = 0.3832 \frac{mev}{ {c} } .$