Question

Find the momentum of a 0.40-lb bullet whose KE is 1600 ft lb

Answer 1

The momentum would be 780.84 kg m/s.

Given:
m = 0.4lb = 181.4 g= 0.18kg
KE= 1600 ftlb = 2169.27 J
To find : Momentum
Solution:

Momentum is outlined as the bulk of motion of the carcass. It is calculated by “mass × speed”, as impetus depends upon speed, and it depends on the route of the motion of the carcass also.
Momentum is a heading abundance because velocity is a heading while bulk is scalar.
The regulation of preservation of push states that the total push of a exclusive arrangement does not change, that method that if two frames pack forcibly each one, their total push subsequently the accident will add up to their push before the accident.

Lets simplify out by formula,
$P = \sqrt{2 m K}\\ P = \sqrt{0.18*2169*2}\\= 780.84 kg m/s$

Hence we get the Momentum = 780.84 kg m/s

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