find the momentum of a body of mass 100 gram having a kinetic energy of 20 Joule
Answers
Answered by
214
K=(1/2)*mv^2=20j
20= (1/2)*(0.1)v^2
V^2=400
V=20
P=mv= 0.1*20=2
P = 2 g*m/s
20= (1/2)*(0.1)v^2
V^2=400
V=20
P=mv= 0.1*20=2
P = 2 g*m/s
shyambiharikushwaha2:
thanks
Answered by
94
Hey there!
We know that Relationship between linear momentum and kinetic energy is
K = p^2/2m.
Given mass of body (m) = 100 g =0.1 kg
Kinetic energy( K) =20 J.
Now,
K = p^2/2m.
20 = p^2/2(0.1)
20*0.2 = p^2
p ^2 =4
p = 2
Therefore, Momentum of body is 2 kg m /s.
It can be obtained in other ways also :-
K=(mv ^2) /2
20 = m v^2 /2
20=0.1/2 v ^2
v^2 = 400
v =20 m/s
We know that,
Momentum P=mv
P =0.1 * 20
P = 2 kg m/s
We know that Relationship between linear momentum and kinetic energy is
K = p^2/2m.
Given mass of body (m) = 100 g =0.1 kg
Kinetic energy( K) =20 J.
Now,
K = p^2/2m.
20 = p^2/2(0.1)
20*0.2 = p^2
p ^2 =4
p = 2
Therefore, Momentum of body is 2 kg m /s.
It can be obtained in other ways also :-
K=(mv ^2) /2
20 = m v^2 /2
20=0.1/2 v ^2
v^2 = 400
v =20 m/s
We know that,
Momentum P=mv
P =0.1 * 20
P = 2 kg m/s
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