Find the monic quadratic in the form x^2+bx+c with solutions x=2-sqrt(3) and x=2+sqrt(3)
Answers
Answered by
2
please mark me as brainliest
Find the monic quadratic in the form +x%5E2+%2B+bx+%2B+c+=+0+ with solutions
+x+=+2%2B-sqrt+%28+3+%29+
Please show working
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
+x+=+2%2B-sqrt+%28+3+%29+
+x-2+=+%22%22%2B-sqrt+%28+3+%29+
+%28x-2%29%5E2+=+%28%22%22%2B-sqrt+%28+3+%29%29%5E2+
+%28x-2%29%5E2+=+3+
+%28x-2%29%5E2+-+3+=+0+
+x%5E2+-+4x+%2B+4+-+3+=+0+
+x%5E2+-+4x+%2B+1+=+0+
-------------------------------------------------------
The answer is +x%5E2+-+4x+%2B+1+=+0+
Similar questions