Question

Find the multiples, if the sum of two consecutive multiples of 6 is 68.

Answer 1

Let the numbers be ೪x and ೪x + 4.

೪x + 4x + 4 = ೬೮

8x + 4 = ೬೮

೮x = ೬೮ - ೪

೮x = ೬೪

x = ೬೪ / ೮

x = ೮

Thus, the numbers are,

4x = ೪ ( ೮ )

= ೩೨

೪x + 4 = ೪ ( ೮ ) + 4

= ೩೨ + ೪

= ೩೬

Hope this helps you.