Question

Find the multiplicative inverse (3+2i)²

Answer 1

)

$Let z be the multiplicative inverse of 3+2i. then</p><p>⇒ z.(3+2i)=1⇒z=3+2i1=(3+2i)(3−2i)3−2i</p><p>⇒ z=133−132i</p><p>(133−132i)</p><p></p><p>$