Question

find the multiplicative inverse of 1+7i/(3-i)^2​

Answer 1

Step-by-step explanation:

First solve

$( {3 - i})^{2}$

you get

$9 + i {}^{2} - 6i$

Fraction is

1+7i

------

$9 + i {}^{2} - 6i$

Inverse is

$9 + i {}^{2} - 6i$

-------------------------

1+7i