Question

Find the multiplicative inverse of (1+i) (1+2i) /(1+3i). Spams will be reported. I want quality answer.​

Answer 1

Answer:

Correct option is

B

13

2+3i

Let Z

i

be the multiplicative Inverse of 2−3i

so that,

Z

i

(2−3i)=1⇒Z

i

=

2−3i

1

=

(2−3i)(2+3i)

2+3i

=

2

2

−(−3

2

)

2+3i

=

(2−3i)(2+3i)

2+3i

=

2

2

+3

2

2+3i

=

13

2

+

13

3i

hope it helps you✌

Answer 2

Answer:

z=1−3i1+2i

=1−3i1+2i×1+3i1+3i

=1−9i21+3i+2i+6i2

=1+9−5+5i

z=(2−1+21i),z−1=(2−1−21i)