Find the multiplicative inverse of 2+3i/4+5i
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hey this is your answer..
Step-by-step explanation:
multiplicative inverse of z=z^-1
multicative inverse of z=1/z
putting z=2-3i
multicative inverse of 2-3i=1/2-3i
rationalising
=1/(2-3i) × (2+3i) / (2+3i)
=2+3i/(2-3i) (2+3i)
using (a+b) (a-b)= a^2 -b^2
=2+3i / 2^2-(3i)^2
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