find the multiplicative inverse of 2-3i?
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Step-by-step explanation:
Let Z
i
be the multiplicative Inverse of 2−3i
so that,
Z
i
(2−3i)=1⇒Z
i
=
2−3i
1
=
(2−3i)(2+3i)
2+3i
=
2
2
−(−3
2
)
2+3i
=
(2−3i)(2+3i)
2+3i
=
2
2
+3
2
2+3i
=
13
2
+
13
3i
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