Find The Multiplicative Inverse of ====>
(x+1) + {1/(x+1)}
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Answers
Answered by
4
Hey there!
Multiplicative inverse is the reciprocal of the number.,which when multiplied by the number gives 1 as a result
(x+1) + 1/(x+1)
=(x+1)²+1/(x+1)
=x²+1+2x+1/(x+1)
=x²+2+2x/(x+1)
Mulitiplicate inverse
=1/Given Number
=1/ [x²+2+2x]/(x+1)
= (x+1)/x²+2+2x
hope helped!
Multiplicative inverse is the reciprocal of the number.,which when multiplied by the number gives 1 as a result
(x+1) + 1/(x+1)
=(x+1)²+1/(x+1)
=x²+1+2x+1/(x+1)
=x²+2+2x/(x+1)
Mulitiplicate inverse
=1/Given Number
=1/ [x²+2+2x]/(x+1)
= (x+1)/x²+2+2x
hope helped!
Answered by
1
Hi 0↓,
Multiplicative inverse of (x+1) + {1/(x+1)} :-
→ take LCM,
LCM is (x+1)
→ {(x+1)²+1}/(x+1)
→ {x²+1²+2(x)(1) + 1}/(x+1)
→ {x²+1+2x+1}/(x+1)
→ {x²+2x+2}/(x+1)
Multiplicative inverse is reciprocal of given number.
→ 1÷(x²+2x+2)/(x+1)
→ (x+1)/(x²+2x+2)
Hope it helps....
Multiplicative inverse of (x+1) + {1/(x+1)} :-
→ take LCM,
LCM is (x+1)
→ {(x+1)²+1}/(x+1)
→ {x²+1²+2(x)(1) + 1}/(x+1)
→ {x²+1+2x+1}/(x+1)
→ {x²+2x+2}/(x+1)
Multiplicative inverse is reciprocal of given number.
→ 1÷(x²+2x+2)/(x+1)
→ (x+1)/(x²+2x+2)
Hope it helps....
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