find the multiplicative inverse of
root 5+2i/ 1-2i
Answers
Step-by-step explanation:
Given:
To find: Multiplicative Inverse of z
Solution:
We know that multiplicative inverse of a/b is b/a
So,
multiplicative inverse of z is 1/z
Multiply and divide by complex conjugate of denominator
Thus,
is the multiplicative inverse of Z.
Hope it helps you.
To learn more on brainly:
1)Find the multiplicative inverse of 1/(4-3i)
https://brainly.in/question/5881172
2)Solve the given quadratic equation:
x² + 3ix + 10 = 0
https://brainly.in/question/7853683
Step-by-step explanation:
Step-by-step explanation:
Given:
\begin{gathered}z = \frac{ \sqrt{5} + 2i}{1 - 2i} \\\end{gathered}
z=
1−2i
5
+2i
To find: Multiplicative Inverse of z
Solution:
We know that multiplicative inverse of a/b is b/a
So,
multiplicative inverse of z is 1/z
\begin{gathered}= \frac{1 - 2i}{ \sqrt{5} + 2i } \\ \\\end{gathered}
=
5
+2i
1−2i
Multiply and divide by complex conjugate of denominator
\begin{gathered}= \frac{1 - 2i}{ \sqrt{5} + 2i} \times \frac{ \sqrt{5} - 2i }{ \sqrt{5} - 2i } \\ \\ = \frac{(1 - 2i)( \sqrt{5} - 2i)}{( \sqrt{5})^{2} + ( {2)}^{2} } \\ \\ = \frac{ \sqrt{5} - 2i - 2 \sqrt{5}i - 4 }{5 + 4} \\ \\ \because \: {i}^{2} = - 1 \\ \\ = \frac{ \sqrt{5} - 4 - 2i (1 + \sqrt{5} )}{9} \\ \\ = \frac{ \sqrt{5} - 4}{9} -i\frac{ 2(1 + \sqrt{5} )}{9}\end{gathered}
=
5
+2i
1−2i
×
5
−2i
5
−2i
=
(
5
)
2
+(2)
2
(1−2i)(
5
−2i)
=
5+4
5
−2i−2
5
i−4
∵i
2
=−1
=
9
5
−4−2i(1+
5
)
=
9
5
−4
−i
9
2(1+
5
)
Thus,
\begin{gathered}\bold{\frac{ \sqrt{5} - 4}{9} -i\frac{ 2(1 + \sqrt{5} )}{9} ) }\\\end{gathered}
9
5
−4
−i
9
2(1+
5
)
)
is the multiplicative inverse of Z.
Hope it helps you.
To learn more on brainly:
1)Find the multiplicative inverse of 1/(4-3i)
https://brainly.in/question/5881172
2)Solve the given quadratic equation:
x² + 3ix + 10 = 0
https://brainly.in/question/7853683