Question

find the multiplicative inverse of
$(2 + \sqrt{3i) {}^{2} }$
​

Answer 1

Let Zi be the multiplicative Inverse of 2−3i

so that, Zi

(2−3i)=1

Zi= 1/2−3i

= 1/(2−3i)(2+3i)

=2+3i/ 2²-(-3³)

=2+3i/(2−3i)(2+3i)

=2+3i/2²+3³

=2/13+3i/13