find the multiplicative inverse of the following:(1)7^-2 (2)9^-9 (3)10^-80
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Solution:
(1) 7^-2 = 1/(7^2)
= 1/49
= 0.0204
(2) 9^-9 = 1/(9^9)
= 1/387420489
(3) 10^-80 = 1/(10^80)
Hope you got your answer.
(1) 7^-2 = 1/(7^2)
= 1/49
= 0.0204
(2) 9^-9 = 1/(9^9)
= 1/387420489
(3) 10^-80 = 1/(10^80)
Hope you got your answer.
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