Question

Find the multiplicative inverse of the following:
(i) 3 + 4i
(ii) √2 + 5i
(iii) 4 - √7i

Answer 1

Answer:

(I) 3+4i

so, multiplicative inverse of 3+4i =1/3+4i

=1(3-4i) /(3+4i) (3-4i)

=3-4i/9+16

=3-4i/25

(ii) √2+5i

so, multiplicative inverse of √2+5i

=1/√2+5i

=1(√2-5i) /2+25

=√2-5i/27

(iii) 4-√7i

so, multiplicative inverse of 4-√7i

=1/4-√7i

=1(4+√7i) /16+7

=4+√7i/23

Answer 2

Answer:

HEY BUDDY HOPE IT HELPS YOU

Step-by-step explanation:

FIND THE MULTIPLICATIVE INVERSE OF THE FOLLOWING :

( i ) 3 + 4i

Multiplicative inverse of 3 + 4i

= 1 / 3 + 4i

= 1 ( 3 - 4i ) / ( 3 + 4i ) ( 3 - 4i )

= 3 - 4i / 9 + 16

= 3 - 4i / 25

THE MULTIPLICATIVE INVERSE OF 3 + 4i

= 3 - 4i / 25

( ii ) √2 + 5i

Multiplicative inverse of √2 + 5i

= 1 / √2 + 5i

= 1 ( √2 - 5i ) / ( √2 + 5i ) ( √2 - 5i )

= √2 - 5i / 2 + 25

= √2 - 5i / 27

THE MULTIPLICATIVE INVERSE OF √2 + 5i

= √2 - 5i / 27

( iii ) 4 - √7i

Multiplicative inverse of 4 - √7i

= 1 / 4 - √7i

= 1 ( 4 + √7i ) / ( 4 - √7i ) ( 4 + √7i )

= 4 + √7i / 16 + 7

= 4 + √7i / 23

THE MULTIPLICATIVE INVERSE OF 4 - √7i

= 4 + √7i / 23