Find the multiplicative inverse of z=2-3i
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Answer:
Given, z=2-3i
Multiplicative inverse of 2-3i is of the form of the (x-iy/x^2+y^2)..
Step-by-step explanation:
= 2-i(3)/2^2+3^2..
= 2-i. 3/4+9
=2-i. 3/13
= 2/13 + i(-3/13)
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