Find the multiplicative
invesse
of (2+i√3)^2
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Answer:
(1-i 4√3) / 49
Step-by-step explanation:
(2+i√3)²
= 2² + 2. 2. i√3 + (i.√3)²
= 4 + i. 4√3 + (-1) . 3
= 4-3+ i. 4√3
= 1+i 4√3
therefore, multiplicative inverse of 1+i 4√3 is 1 / (1+i 4√3)
1 / (1+i 4√3) = 1 / (1+i 4√3) * (1-i 4√3) / (1-i 4√3)
= (1-i 4√3) / (1+i 4√3)(1-i 4√3)
= (1-i 4√3) / 1² - (i4√3)²
= (1-i 4√3) / 1 - (-1)(16)(3)
= (1-i 4√3) / 1 +48
= (1-i 4√3) / 49
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