find the multiplicatve inverse ofcomplex number 4+3i
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Answer:
Multiplicative inverse of 4+3i= 4-3i/25
Step-by-step explanation:
Lest us assume,
Let z= 4+3i
then z~=4-3i
|z~|^2= 4^2+3^2
= 16+9
= 25
|z~|^2=25
z^-1= z~/|z~|^2
=4-3i/25
z~^-1= 4-3i/25
I hope this will help you...
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